您好!
Kernel SIG 邀请您参加 2023-02-10 14:00 召开的Zoom会议(自动录制)
会议主题:openEuler Kernel SIG双周例会
会议内容: 欢迎您参加年后第一次Kernel SIG 双周例会: 1. 进展update 2. 议题征集中 欢迎大家积极申报议题(新增议题可以直接回复邮件,或录入会议看板)
会议链接:https://us06web.zoom.us/j/89146789515?pwd=NVN5RmdCSFh2Y1g4SXUwK2NCRnFEZz09
会议纪要:https://etherpad.openeuler.org/p/Kernel-meetings
温馨提醒:建议接入会议后修改参会人的姓名,也可以使用您在gitee.com的ID
更多资讯尽在:https://openeuler.org/zh/
Hello!
openEuler Kernel SIG invites you to attend the Zoom conference(auto recording) will be held at 2023-02-10 14:00,
The subject of the conference is openEuler Kernel SIG双周例会,
Summary: 欢迎您参加年后第一次Kernel SIG 双周例会: 1. 进展update 2. 议题征集中 欢迎大家积极申报议题(新增议题可以直接回复邮件,或录入会议看板)
You can join the meeting at https://us06web.zoom.us/j/89146789515?pwd=NVN5RmdCSFh2Y1g4SXUwK2NCRnFEZz09.
Add topics at https://etherpad.openeuler.org/p/Kernel-meetings.
Note: You are advised to change the participant name after joining the conference or use your ID at gitee.com.
More information: https://openeuler.org/en/
申报一个议题:英特尔平台几个复杂特性的代码情况说明和讨论
thanks, Jason
On Tue, Feb 07, 2023 at 08:42:54AM +0000, openEuler conference wrote:
您好!
Kernel SIG 邀请您参加 2023-02-10 14:00 召开的Zoom会议(自动录制)
会议主题:openEuler Kernel SIG双周例会
会议内容: 欢迎您参加年后第一次Kernel SIG 双周例会:
- 进展update
- 议题征集中
欢迎大家积极申报议题(新增议题可以直接回复邮件,或录入会议看板)
会议链接:https://us06web.zoom.us/j/89146789515?pwd=NVN5RmdCSFh2Y1g4SXUwK2NCRnFEZz09
会议纪要:https://etherpad.openeuler.org/p/Kernel-meetings
温馨提醒:建议接入会议后修改参会人的姓名,也可以使用您在gitee.com的ID
更多资讯尽在:https://openeuler.org/zh/
Hello!
openEuler Kernel SIG invites you to attend the Zoom conference(auto recording) will be held at 2023-02-10 14:00,
The subject of the conference is openEuler Kernel SIG双周例会,
Summary: 欢迎您参加年后第一次Kernel SIG 双周例会:
- 进展update
- 议题征集中
欢迎大家积极申报议题(新增议题可以直接回复邮件,或录入会议看板)
You can join the meeting at https://us06web.zoom.us/j/89146789515?pwd=NVN5RmdCSFh2Y1g4SXUwK2NCRnFEZz09.
Add topics at https://etherpad.openeuler.org/p/Kernel-meetings.
Note: You are advised to change the participant name after joining the conference or use your ID at gitee.com.
More information: https://openeuler.org/en/
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